Integrand size = 26, antiderivative size = 69 \[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=-\frac {3 i \sqrt [6]{2} a \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {5}{6},\frac {1}{6},\frac {1}{2} (1-i \tan (e+f x))\right ) (1+i \tan (e+f x))^{5/6}}{5 f (d \sec (e+f x))^{5/3}} \]
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Time = 0.20 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3586, 3604, 72, 71} \[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=-\frac {3 i \sqrt [6]{2} a (1+i \tan (e+f x))^{5/6} \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {5}{6},\frac {1}{6},\frac {1}{2} (1-i \tan (e+f x))\right )}{5 f (d \sec (e+f x))^{5/3}} \]
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Rule 71
Rule 72
Rule 3586
Rule 3604
Rubi steps \begin{align*} \text {integral}& = \frac {\left ((a-i a \tan (e+f x))^{5/6} (a+i a \tan (e+f x))^{5/6}\right ) \int \frac {\sqrt [6]{a+i a \tan (e+f x)}}{(a-i a \tan (e+f x))^{5/6}} \, dx}{(d \sec (e+f x))^{5/3}} \\ & = \frac {\left (a^2 (a-i a \tan (e+f x))^{5/6} (a+i a \tan (e+f x))^{5/6}\right ) \text {Subst}\left (\int \frac {1}{(a-i a x)^{11/6} (a+i a x)^{5/6}} \, dx,x,\tan (e+f x)\right )}{f (d \sec (e+f x))^{5/3}} \\ & = \frac {\left (a^2 (a-i a \tan (e+f x))^{5/6} \left (\frac {a+i a \tan (e+f x)}{a}\right )^{5/6}\right ) \text {Subst}\left (\int \frac {1}{\left (\frac {1}{2}+\frac {i x}{2}\right )^{5/6} (a-i a x)^{11/6}} \, dx,x,\tan (e+f x)\right )}{2^{5/6} f (d \sec (e+f x))^{5/3}} \\ & = -\frac {3 i \sqrt [6]{2} a \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {5}{6},\frac {1}{6},\frac {1}{2} (1-i \tan (e+f x))\right ) (1+i \tan (e+f x))^{5/6}}{5 f (d \sec (e+f x))^{5/3}} \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.91 \[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=-\frac {3 a \left (i+\cot (e+f x) \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {1}{2},\frac {1}{6},\sec ^2(e+f x)\right ) \sqrt {-\tan ^2(e+f x)}\right )}{5 f (d \sec (e+f x))^{5/3}} \]
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\[\int \frac {a +i a \tan \left (f x +e \right )}{\left (d \sec \left (f x +e \right )\right )^{\frac {5}{3}}}d x\]
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\[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=\int { \frac {i \, a \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {5}{3}}} \,d x } \]
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\[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=i a \left (\int \left (- \frac {i}{\left (d \sec {\left (e + f x \right )}\right )^{\frac {5}{3}}}\right )\, dx + \int \frac {\tan {\left (e + f x \right )}}{\left (d \sec {\left (e + f x \right )}\right )^{\frac {5}{3}}}\, dx\right ) \]
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\[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=\int { \frac {i \, a \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {5}{3}}} \,d x } \]
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\[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=\int { \frac {i \, a \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {5}{3}}} \,d x } \]
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Timed out. \[ \int \frac {a+i a \tan (e+f x)}{(d \sec (e+f x))^{5/3}} \, dx=\int \frac {a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}{{\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^{5/3}} \,d x \]
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